簡單嚟講就係同冷氣原理相同既嘢,但一頭攞熱之餘另一頭都攞凍嚟用
QH=QC+W
to the hot reservoir and Qcold is the heat collected from the cold heat reservoir.
V = Q/ (cp)(△T)(d)
V = airflow rate; (m3/s)
Q = Total heat emitted; (kW)
cp = Specific heat of Air; (1.01 kJ/kg/oK)
△T = Genset room temperature rise; (oK), 跟據EMSD CoP, 最高溫度係40, 假設吹入lift shaft散熱嘅風係由室外吹入去,跟據BEEO 2018, outdoor design temperature 係35度,即係(40-35)=5
d = Density of air (1.20 kg/m3)
V = 1.84/(1.01*1.2*5) = 0.304m^3/s
之後就要先搵個static出嚟,搵風扇也好,泵也好,Static+Flow Rate係必備。假設Lift shaft 係2.9m x 5.2m x 53.2m(H), 頂同底有兩個0.3 meter square嘅louver, 咁個static應該點計?
首先假設咗成條lift shaft係一條石屎風喉;由於條shaft太大以致唔可能由CIBSE Guide C搵到送風嘅有效面積,所以一般會以橫切面嘅方形畫到最大嘅圓形直徑嚟估算,即係2.9m. 之後我地再用google大神search "concrete duct friction loss calculator"類似字眼,就會搵到大量嘅online calculator, 就以 Good Calculators 為例子,輸入晒數據就可以發現,原來呢個風量嘅情況下,個pressure drop (or say friction loss) 係可以ignore:
再之後估算一個louver個pressure drop有幾多,一般顧問會say落去如10-50Pa; 又或者可以大概計下,都係可以用google大神search "louver pressure drop calculator" or "louver pressure catalogue":
Air volume flow rate, louvre area等數都有(留意係入個有效面積,即係如果係一個0.3m x 1m = 0.3meter square嘅builder窿,一般係會take返0.5 efficiency, 即係0.15 meter square); 而個discharge loss coefficient 可以搵啲類似嘅catalogue攞返個數。計完之後,見到個pressure大概係17Pa, 一上一下兩個louvre即係34Pa.
最後要check埋把扇達唔達到"10ACH for machine room or machinery space at the top of the well and its associated working space for machine room-less lift"要求,一般係lift shaft overrun嘅volume除一個鐘頭嘅秒數3600, 設overrun為5m
2.9m x 5.2m x 5m x 10 / 3600 = 0.209m^3/s
0.304m^3/s > 0.209m^3/s,所以係滿足得埋條件4.所要求嘅10ACH.
之後就可以去catalogue揀風扇﹕
為咗滿足條件2.嘅要求,當然係要搵啲有兩段速以上嘅風扇。
(Source: 香港電梯資料網 hkelev.com)